Three Dimensional Geometry Question - CBSE

Question

The equation of a line passing through $(2, -1, 4)$ and parallel to vector $\hat{i} + \hat{j} - 2\hat{k}$ in Cartesian form is:
(a) $\dfrac{x-2}{1} = \dfrac{y+1}{1} = \dfrac{z-4}{-2}$
(b) $\dfrac{x+2}{1} = \dfrac{y-1}{1} = \dfrac{z+4}{-2}$
(c) $\dfrac{x-1}{2} = \dfrac{y-1}{-1} = \dfrac{z+2}{4}$
(d) $\dfrac{x-2}{1} = \dfrac{y-1}{1} = \dfrac{z-4}{2}$

Accepted Answer

Cartesian form: $\dfrac{x-2}{1} = \dfrac{y+1}{1} = \dfrac{z-4}{-2}$. [1.0 Mark]

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🎯 Official CBSE Marking Scheme:
Selecting correct Cartesian line equation: 1.0 Mark

Question:

Step-by-Step Solution

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