If one zero of $2x^2 - 3x + p$ is $3$ times the other, find $p$.
Step-by-Step Solution
Key Concept: Zeroes $\alpha, 3\alpha$. Sum $4\alpha = 3/2 \Rightarrow \alpha = 3/8$. Product $3\alpha^2 = p/2 \Rightarrow p = 6\alpha^2 = 6(9/64) = 27/32$.
$4\alpha = 3/2 \Rightarrow \alpha = 3/8$. [1.5 Marks]
Product $= 3(3/8)^2 = 3(9/64) = 27/64 = p/2 \Rightarrow p = 27/32$. [1.5 Marks]
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🎯 Official CBSE Marking Scheme:
Finding $\alpha = 3/8$: 1.5 Marks
Evaluating $p = 27/32$: 1.5 Marks
Correct Answer: