Inverse Trigonometric Functions
NCERT Exemplar Class 12
CBSE
Grade 12
Question:
The value of $\sin\left(\cos^{-1} \dfrac{4}{5}\right)$ is:
(a) $\dfrac{3}{5}$
(b) $\dfrac{4}{5}$
(c) $\dfrac{1}{5}$
(d) $\dfrac{2}{5}$
Step-by-Step Solution
\sin(\cos^{-1}(4/5)) = \sqrt{1 - 16/25} = 3/5. [1.0 Mark]
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🎯 Official CBSE Marking Scheme:
Selecting $3/5$: 1.0 Mark
Correct Answer: $\dfrac{3}{5}$
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