Continuity and Differentiability
NCERT Class 12
CBSE
Grade 12
Question:
Differentiate $e^{\sin^{-1} x}$ with respect to $x$.
Step-by-Step Solution
$e^{\sin^{-1} x} \cdot \dfrac{1}{\sqrt{1-x^2}} = \dfrac{e^{\sin^{-1} x}}{\sqrt{1-x^2}}$. [2.0 Marks]
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🎯 Official CBSE Marking Scheme:
Evaluating derivative $= e^{\sin^{-1}x}/\sqrt{1-x^2}$: 2.0 Marks
Correct Answer:
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