Trigonometry & Inverse Trigonometry
Heights And Distances
nta_abhyas_2025
Grade 11

Question:

$\angle PQS = 90° = \angle PRS = 90°$

Step-by-Step Solution

Key Concept: Points equidistant from the foot of a tower and subtending equal angles to the top form vertices of a cyclic quadrilateral
Let $T$ be the top of the tower and $F$ be the foot of the tower with height $h$. Since $\angle TPF = \theta$ is a right-angled triangle, we have $PF = h\cot\theta$. Similarly, $QF = RF = SF = h\cot\theta$, which means points $P, Q, R, S$ all lie on a circle. Since $P, Q, R, S$ are vertices of a cyclic quadrilateral, they may or may not be consecutive vertices in the same order. Therefore, options A, B, and D may or may not be correct, but option C (stating the geometric relationship) is always correct.
Correct Answer: 3

Master Trigonometry & Inverse Trigonometry with Mathbee

Practice this topic under real exam conditions with strict timers, or ask our AI Mentor to explain the concepts step-by-step.

Start Practicing for Free