Trigonometry
Product of cosines using Chebyshev/telescoping identities
MMTS_Full_Test_20
Grade 12

Question:

The value of $\displaystyle\prod_{r=1}^{7} \cos\frac{r\pi}{15}$ is
(A) $\dfrac{1}{64}$
(B) $\dfrac{1}{128}$
(C) $\dfrac{1}{32}$
(D) $\dfrac{1}{4}$

Step-by-Step Solution

Key Concept: Group the product and use known results: $\prod_{r=1}^{n-1}\sin\frac{r\pi}{n}=\frac{n}{2^{n-1}}$. Alternatively group into subproducts with known values.
Product $= \frac{1}{16}\cdot\frac{1}{4}\cdot\frac{1}{2} = \frac{1}{128}$.
Correct Answer: (B) $\dfrac{1}{128}$

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