Inverse Trigonometric Functions
NCERT Exemplar Class 12
CBSE
Grade 12
Question:
Find the principal value of $\cot^{-1}(-1)$.
Step-by-Step Solution
\cot^{-1}(-1) = \pi - \cot^{-1}(1). [1.0 Mark]
$= \pi - \pi/4 = 3\pi/4$. [1.0 Mark]
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🎯 Official CBSE Marking Scheme:
Applying identity $\cot^{-1}(-x) = \pi - \cot^{-1} x$: 1.0 Mark
Evaluating principal value $= 3\pi/4$: 1.0 Mark
Correct Answer:
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