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Real Numbers
RD Sharma
CBSE
Grade 10
Question:
A sweet seller has $420$ Kaju barfis and $130$ Badam barfis. She wants to stack them in such a way that each stack has the same number, and they take up the least area of the tray. What is the maximum number of barfis that can be placed in each stack for this purpose?
Step-by-Step Solution
Key Concept: $\\text{HCF}(420, 130) = 10$.
$420 = 2^2 \times 3 \times 5 \times 7$, $130 = 2 \times 5 \times 13$. [1.5 Marks] $\text{HCF}(420, 130) = 2 \times 5 = 10$. Maximum number per stack is $10$. [1.5 Marks]
--- 🎯 Official CBSE Marking Scheme: Prime factorisation: 1.5 Marks Evaluating HCF $= 10$: 1.5 Marks
Correct Answer:
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