<p>The locus of the middle point of the chords of parabola \(y^2 = 4x\) which are normal to parabola is</p>
Step-by-Step Solution
Key Concept: Use the equation of normal to parabola and find locus of midpoints by eliminating the parameter.
<p>For chords normal to the parabola \(y^2 = 4x\), the locus of midpoints satisfies the equation obtained by eliminating the parameter from normal chord conditions. The resulting locus is \(y^4 + 4(1-x)y^2 + 4(1-4x) = 0\).</p>
Correct Answer: p