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Determinants
NCERT Exemplar Class 12
CBSE
Grade 12

Question:

Solve the following system of equations by matrix method:
$\dfrac{2}{x} + \dfrac{3}{y} + \dfrac{10}{z} = 4, \dfrac{4}{x} - \dfrac{6}{y} + \dfrac{5}{z} = 1, \dfrac{6}{x} + \dfrac{9}{y} - \dfrac{20}{z} = 2$.

Step-by-Step Solution

Given: Problem statement: Solve the following system of equations by matrix method:
$\dfrac{2}{x} + \dfrac{3}{y} + \dfrac{10}{z} = 4, \dfrac{4}{x} - \dfrac{6}{y} + \dfrac{5}{z} = 1, \dfrac{6}{x} + \dfrac{9}{y} - \dfrac{20}{z} = 2$.
Step 1: Form Matrix Equation $AX = B$:
Write coefficient matrix $A$, variable vector $X$, and constant vector $B$. [1.0 Mark]
Step 2: Evaluate Determinant $|A|$:
Check if $|A|
eq 0$ so that inverse $A^{-1}$ exists. [1.0 Mark]
Step 3: Compute Adjugate Matrix $\text{adj } A$:
Find cofactors of all elements and transpose matrix of cofactors. [1.0 Mark]
Step 4: Compute Inverse $A^{-1}$:
Apply $A^{-1} = \frac{1}{|A|} \text{adj } A$. [1.0 Mark]
Step 5: Solve for $X = A^{-1} B$:
Multiply $A^{-1} B$ to obtain exact values of $x, y, z$. [1.0 Mark]
Conclusion: Values of variables determined accurately.

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🎯 Official CBSE Marking Scheme:
Setting up matrix system AX = B: 1.0 Mark
Evaluating determinant |A|: 1.0 Mark
Evaluating cofactors and adjugate matrix: 1.0 Mark
Evaluating inverse matrix A^-1: 1.0 Mark
Multiplying A^-1 B to solve x, y, z: 1.0 Mark

Correct Answer:
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