Find the zeroes of $f(x) = a b x^2 + (b^2 - a c) x - b c$.
Step-by-Step Solution
Key Concept: $a b x^2 + b^2 x - a c x - b c = 0 \Rightarrow b x(a x + b) - c(a x + b) = 0 \Rightarrow (a x + b)(b x - c) = 0$.
$b x(a x + b) - c(a x + b) = 0 \Rightarrow (a x + b)(b x - c) = 0$. [1.5 Marks]
Zeroes are $x = -b/a$ and $x = c/b$. [1.5 Marks]
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🎯 Official CBSE Marking Scheme:
Factoring into $(ax+b)(bx-c)$: 1.5 Marks
Finding zeroes $-b/a$ and $c/b$: 1.5 Marks
Correct Answer: