Application of Derivatives
NCERT Class 12
CBSE
Grade 12
Question:
Find the rate of change of the area of a circle with respect to its radius $r$ when $r = 5\text{ cm}$.
Step-by-Step Solution
$\dfrac{dA}{dr} = 2\pi r = 2\pi(5) = 10\pi\text{ cm}^2/\text{cm}$. [2.0 Marks]
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🎯 Official CBSE Marking Scheme:
Evaluating rate of change $= 10\pi$ cm$^2$/cm: 2.0 Marks
Correct Answer:
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