Definite Integration
Area under parabola
Grade 12
Question:
<p>If the area bounded between x-axis and the graph of <i>y</i> = 6<i>x</i> – 3<i>x</i>² between the ordinates <i>x</i> = 1 and <i>x</i> = <i>a</i> is 19 square units then '<i>a</i>' can take the value</p>
<p>(A) 4 or –2</p>
<p>(B) two values are in (2, 3) and one in (–1, 0)</p>
<p>(C) two values one in (3,4) and one in (–2,–1)</p>
<p>(D) none of these</p>
Step-by-Step Solution
Key Concept: Set up the definite integral equation and solve for the variable limit a where the area equals 19 square units. The absolute value of area may result in multiple solutions.
<p>Not provided in source text</p>
Correct Answer: A