Inverse Trigonometric Functions
NCERT Class 12
CBSE
Grade 12
Question:
Find the value of $\sin^{-1}\left(\sin \dfrac{3\pi}{5}\right)$.
Step-by-Step Solution
$\sin(3\pi/5) = \sin(\pi - 2\pi/5) = \sin(2\pi/5)$. [1.0 Mark]
Since $2\pi/5 \in [-\pi/2, \pi/2]$, value $= 2\pi/5$. [1.0 Mark]
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🎯 Official CBSE Marking Scheme:
Rewriting angle into principal domain: 1.0 Mark
Evaluating value $= 2\pi/5$: 1.0 Mark
Correct Answer:
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