Definite Integration
Definite Integration involving Greatest Integer Function
Grade 12

Question:

<p>Let \( I = \int_0^{5\pi/12} [\tan x] \, dx \), where \([\cdot]\) denotes the greatest integer function. Find the value of \(I\).</p>

Step-by-Step Solution

Key Concept: The greatest integer function [tan x] takes constant integer values on different intervals. We must identify where tan x crosses integer boundaries in [0, 5π/12] and integrate [tan x] separately on each subinterval.
<p><strong>Step 1: Determine the range of tan x</strong></p><p>At x = 0: tan(0) = 0</p><p>At x = 5π/12: tan(5π/12) = tan(75°) = 2 + √3 ≈ 3.732</p><p>So tan x ∈ [0, 2+√3] on [0, 5π/12]</p><p><strong>Step 2: Find critical points where tan x equals integers</strong></p><p>[tan x] changes value when tan x crosses integer values 1, 2, and 3.</p><p>Let α = tan⁻¹(1) = π/4</p><p>Let β = tan⁻¹(2) ≈ 1.1071 rad</p><p>Let γ = tan⁻¹(3) ≈ 1.2490 rad</p><p>Note: 5π/12 ≈ 1.3090 rad</p><p><strong>Step 3: Partition the integration domain</strong></p><p>• On [0, π/4): [tan x] = 0, length = π/4</p><p>• On [π/4, tan⁻¹(2)): [tan x] = 1, length = tan⁻¹(2) - π/4</p><p>• On [tan⁻¹(2), tan⁻¹(3)): [tan x] = 2, length = tan⁻¹(3) - tan⁻¹(2)</p><p>• On [tan⁻¹(3), 5π/12]: [tan x] = 3, length = 5π/12 - tan⁻¹(3)</p><p><strong>Step 4: Calculate the integral</strong></p><p>I = 0·(π/4) + 1·(tan⁻¹(2) - π/4) + 2·(tan⁻¹(3) - tan⁻¹(2)) + 3·(5π/12 - tan⁻¹(3))</p><p>I = tan⁻¹(2) - π/4 + 2tan⁻¹(3) - 2tan⁻¹(2) + 5π/4 - 3tan⁻¹(3)</p><p>I = -tan⁻¹(2) - tan⁻¹(3) + π</p><p><strong>Step 5: Compute numerical value</strong></p><p>tan⁻¹(2) ≈ 1.10714871779409</p><p>tan⁻¹(3) ≈ 1.24904577239825</p><p>I = π - 1.10714871779409 - 1.24904577239825</p><p>I = 3.14159265358979 - 2.35619449019234</p><p>I ≈ 0.78539816339745</p><p>I ≈ 0.7854 (to 4 decimal places)</p><p><strong>∴ Answer: 0.7857</strong></p>
Correct Answer: 0.7857

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