The area of the region, inside the ellipse $x^2+4y^2=4$ and outside the region bounded by the curves $y=|x|-1$ and $y=1-|x|$, is:
Step-by-Step Solution
Key Concept: Ellipse: $\frac{x^2}{4}+y^2=1$ with $a=2,b=1$, area $=\pi ab=2\pi$. Curves $y=|x|-1$ and $y=1-|x|$ intersect at $(\pm1,0)$ and $(0,\pm1)$, forming a rhombus with vertices $(0,1),(1,0),(0,-1),(-1,0)$.
Ellipse area $=2\pi$, rhombus area $=2$. Required $=2(\pi-1)$.
Correct Answer: 4