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Three Dimensional Geometry
NCERT Exemplar Class 12
CBSE
Grade 12
Question:
Find vector equation of line passing through $(1, 2, 3)$ and parallel to line $\dfrac{x-2}{3} = \dfrac{y+1}{4} = \dfrac{z-4}{2}$.
Step-by-Step Solution
Given: Find vector equation of line passing through $(1, 2, 3)$ and parallel to line $\dfrac{x-2}{3} = \dfrac{y+1}{4} = \dfrac{z-4}{2}$. Step 1: Set up the governing mathematical relation / formula: From the given problem statement, we state the key relation: $$r$$ [1.0 Mark] Step 2: Execute step-by-step evaluation and simplify: Evaluating and simplifying the expression: $$(i + 2j + 3k) + \lambda(3i + 4j + 2k).$$ [1.0 Mark] Conclusion: The solution is verified as (i + 2j + 3k) + \lambda(3i + 4j + 2k)..
--- 🎯 Official CBSE Marking Scheme: Setting up equation / formula: 1.0 Mark Evaluating correct final answer: 1.0 Mark
Correct Answer:
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