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Introduction to Trigonometry
CH08 Question Bank
CBSE_CH08_QUESTION_BANK
Grade 10
Question:
In the given right triangle, $\tan\theta$ equals:
$\dfrac{5}{12}$
$\dfrac{12}{5}$
$\dfrac{5}{13}$
$\dfrac{12}{13}$
$\dfrac{5}{12}$
$\dfrac{12}{5}$
$\dfrac{5}{13}$
$\dfrac{12}{13}$
Step-by-Step Solution
Key Concept: $\tan\theta=\dfrac{\text{opposite}}{\text{adjacent}}$.
$\tan\theta=\dfrac{AB}{BC}=\dfrac{5}{12}$. [1.0 Mark]
Correct Answer: $\dfrac{5}{12}$
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