<p>The number of 5 letter words formed with the letters of the word CALCULUS is divisible by:</p>
Step-by-Step Solution
Key Concept: Count permutations of letters accounting for repetitions, then find divisibility properties of the resulting count.
<p>The word CALCULUS has 8 letters: C, A, L, C, U, L, U, S with repetitions: C appears 2 times, L appears 2 times, U appears 2 times, and A, S appear once each.</p><p>Number of 5-letter words = sum of ways to select 5 letters from the available letters considering their multiplicities, then arrange them. After computation, this number is divisible by 2, 3, and 5.</p>
Correct Answer: a, b, c