Three Dimensional Geometry
NCERT Class 12
CBSE
Grade 12
Question:
Find the coordinates of the foot of perpendicular from point $(2, 3, -8)$ to the line $\dfrac{x-4}{2} = \dfrac{y+1}{-1} = \dfrac{z-3}{4}$.
Step-by-Step Solution
Perpendicular condition: $21\lambda + 21 = 0 \Rightarrow \lambda = -1$. [1.5 Marks]
Foot of perpendicular $M = (2, 0, -1)$. [1.5 Marks]
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🎯 Official CBSE Marking Scheme:
Setting up perpendicularity equation: 1.5 Marks
Evaluating foot of perpendicular $M = (2, 0, -1)$: 1.5 Marks
Correct Answer:
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