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Three Dimensional Geometry
NCERT Exemplar Class 12
CBSE
Grade 12
Question:
Equation of line passing through origin and $(5, -2, 3)$ is: (a) $\dfrac{x}{5} = \dfrac{y}{-2} = \dfrac{z}{3}$ (b) $\dfrac{x-5}{5} = \dfrac{y+2}{-2} = \dfrac{z-3}{3}$ (c) $\dfrac{x}{5} = \dfrac{y}{2} = \dfrac{z}{3}$ (d) None of these
Step-by-Step Solution
Line through (0,0,0) with d.r. 5, -2, 3. [1.0 Mark]
--- 🎯 Official CBSE Marking Scheme: Selecting $\dfrac{x}{5} = \dfrac{y}{-2} = \dfrac{z}{3}$: 1.0 Mark