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Algebra
Arithmetic Progressions, Sum of Series
jee_main_2026_april_8_shift_1
Grade None

Question:

The sum of the first 12 terms of the AP: 1, 4, 7, 10, ... is:

Step-by-Step Solution

Key Concept: S_n = n/2[2a + (n-1)d].
Step 1: S_12 = 12/2[2(1) + (12-1)3] = 6[2 + 33] = 6 × 35 = 210.
Correct Answer: 210
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