Application of Integrals
NCERT Class 12
CBSE
Grade 12
Question:
Find area of the region bounded by $y = x^2 + 2$, $y = x$, $x = 0$ and $x = 3$.
Step-by-Step Solution
$\int_0^3 (x^2 - x + 2) dx = \left[ \dfrac{x^3}{3} - \dfrac{x^2}{2} + 2x \right]_0^3$. [1.5 Marks]
$= 9 - 4.5 + 6 = 21/2$ sq. units. [1.5 Marks]
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🎯 Official CBSE Marking Scheme:
Setting up difference integral: 1.5 Marks
Evaluating area $= 21/2$ sq. units: 1.5 Marks
Correct Answer:
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