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Coordinate Geometry

RD Sharma

CBSE

Grade 10

Question:

The perimeter of a triangle with vertices $(0, 0), (0, 3)$ and $(4, 0)$ is:
(a) $12$
(b) $7$
(c) $5$
(d) $14$

Step-by-Step Solution

Key Concept: Sides are $3, 4$ and $\sqrt{3^2 + 4^2} = 5$. Perimeter $= 3 + 4 + 5 = 12$.

$3 + 4 + 5 = 12$. [1.0 Mark]

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🎯 Official CBSE Marking Scheme:
Calculating perimeter $= 12$: 1.0 Mark

Correct Answer: $12$

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