Find the probability of getting $53$ Sundays in a leap year.
Step-by-Step Solution
Key Concept: Leap year $= 366$ days $= 52$ weeks $+ 2$ extra days.<br>Possible pairs for 2 extra days: $(Sun, Mon), (Mon, Tue), (Tue, Wed), (Wed, Thu), (Thu, Fri), (Fri, Sat), (Sat, Sun)$ (7 pairs).<br>Favourable pairs containing Sunday $= 2$. $P = 2/7$.
2 extra days can form 7 pairs of consecutive days. [1.0 Mark]
Favourable pairs with Sunday $= 2 \Rightarrow P = 2/7$. [1.0 Mark]
---
🎯 Official CBSE Marking Scheme:
Identifying 2 extra days & 7 sample space pairs: 1.0 Mark
Evaluating probability $= 2/7$: 1.0 Mark
Correct Answer: