Inverse Trigonometric Functions
NCERT Class 12
CBSE
Grade 12
Question:
Find the domain of the function $f(x) = \sin^{-1}(x^2 - 1)$.
Step-by-Step Solution
$-1 \le x^2 - 1 \le 1 \Rightarrow 0 \le x^2 \le 2$. [1.0 Mark]
$\Rightarrow x \in [-\sqrt{2}, \sqrt{2}]$. [1.0 Mark]
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🎯 Official CBSE Marking Scheme:
Setting up inequality $-1 \le x^2-1 \le 1$: 1.0 Mark
Evaluating domain $= [-\sqrt{2}, \sqrt{2}]$: 1.0 Mark
Correct Answer:
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