Question:
The latus rectum of a conic section is the width of the function through the focus. The positive difference between the length of the latus rectum of <span class="math-inline">3y = x^2 + 4x - 9</span> and <span class="math-inline">x^2 + 4y^2 - 6x + 16y - 24</span> is -
\frac{1}{2}
2
\frac{3}{2}
\frac{5}{2}
Step-by-Step Solution
Key Concept: General
y² + b² = c²(x² - a²)
Correct Answer: Ans.(B)