Question:

Image of $P(2,3,5)$ in $2x+y-3z=6$ is $(\alpha,\beta,\gamma)$. Then $\alpha+\beta+\gamma$ is equal to

Step-by-Step Solution

Key Concept: Reflection formula: $Q=P-2\frac{(\vec{n}\cdot\vec{OP}-d)}{|\vec{n}|^2}\vec{n}$.

$\alpha+\beta+\gamma=10$.

Correct Answer: 2