Integrals
NCERT Class 12
CBSE
Grade 12
Question:
$\int e^x \left(\dfrac{1}{x} - \dfrac{1}{x^2}\right) dx$ is equal to:
(a) $\dfrac{e^x}{x} + C$
(b) $-\dfrac{e^x}{x} + C$
(c) $\dfrac{e^x}{x^2} + C$
(d) $e^x \log x + C$
Step-by-Step Solution
$\int e^x \left[ \dfrac{1}{x} - \dfrac{1}{x^2} \right] dx = \dfrac{e^x}{x} + C$. [1.0 Mark]
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🎯 Official CBSE Marking Scheme:
Evaluating integral $= e^x/x + C$: 1.0 Mark
Correct Answer: $\dfrac{e^x}{x} + C$
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