Coordinate Geometry
RD Sharma
CBSE
Grade 10
Question:
The ratio in which the $x$-axis divides the segment joining $A(2, -3)$ and $B(5, 6)$ is:
(a) $1 : 2$
(b) $2 : 1$
(c) $1 : 3$
(d) $3 : 1$
Step-by-Step Solution
Key Concept: On $x$-axis, $y = 0 \Rightarrow \dfrac{k(6) + 1(-3)}{k + 1} = 0 \Rightarrow 6k = 3 \Rightarrow k = 1/2 \Rightarrow 1 : 2$.
$6k - 3 = 0 \Rightarrow k = 1/2 \Rightarrow 1 : 2$. [1.0 Mark]
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🎯 Official CBSE Marking Scheme:
Evaluating ratio $1 : 2$: 1.0 Mark
Correct Answer: $1 : 2$
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