Inverse Trigonometric Functions
NCERT Class 12
CBSE
Grade 12
Question:
If $\tan^{-1} x = y$, then $y$ lies in:
(a) $\left(-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right)$
(b) $\left[-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right]$
(c) $(0, \pi)$
(d) $[0, \pi]$
Step-by-Step Solution
Range of $\tan^{-1} x$ is $(-\pi/2, \pi/2)$. [1.0 Mark]
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🎯 Official CBSE Marking Scheme:
Selecting $(-\pi/2, \pi/2)$: 1.0 Mark
Correct Answer: $\left(-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right)$
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