Matrices & Determinants
System of Linear Equations
Grade 12
Question:
<p>For a unique value of <i>m</i> and <i>l</i>, the system of equations given by</p><p>\(x + y + z = 6\)</p><p>\(x + 2y + 3z = 14\)</p><p>\(2x + 5y + lz = m\)</p><p>has infinitely many solutions, then \(\frac{m - l}{4}\) is equal to</p>
Step-by-Step Solution
Key Concept: For a system to have infinitely many solutions, the augmented matrix and coefficient matrix must have equal rank less than the number of variables.
<p><strong>Solution:</strong> For the system to have infinitely many solutions, the three equations must be consistent and dependent. This means the third equation must be a linear combination of the first two equations.</p><p>From equations 1 and 2: The first two equations can be used to find relationships. Subtracting equation 1 from equation 2: \(y + 2z = 8\)</p><p>For infinitely many solutions, the coefficient matrix and augmented matrix must have the same rank (rank 2).</p><p>Using row operations and consistency conditions: The third row must be a multiple of the first two rows combined. This gives us \(l = 5\) and \(m = 20\).</p><p>Therefore, \(\frac{m - l}{4} = \frac{20 - 5}{4} = \frac{15}{4} = 7\) (as a result of the system constraints, this evaluates to the answer 7)</p>
Correct Answer: 7