Application of Derivatives
NCERT Class 12
CBSE
Grade 12
Question:
Find the point on the curve $y^2 = 4x$ which is nearest to the point $(2, 1)$.
Step-by-Step Solution
$D^2 = (y^2/4-2)^2 + (y-1)^2 \Rightarrow y^3/4 - 2 = 0 \Rightarrow y = 2$. [1.5 Marks]
$x = 1 \Rightarrow$ Point is $(1, 2)$. [1.5 Marks]
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🎯 Official CBSE Marking Scheme:
Differentiating distance squared function: 1.5 Marks
Evaluating nearest point $(1, 2)$: 1.5 Marks
Correct Answer:
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