Application of Derivatives
NCERT Class 12
CBSE
Grade 12
Question:
The minimum value of $f(x) = |x + 2| - 1$ is:
(a) $-1$
(b) $-2$
(c) $0$
(d) $1$
Step-by-Step Solution
$|x+2| \ge 0 \Rightarrow \text{Min value} = -1$ at $x = -2$. [1.0 Mark]
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🎯 Official CBSE Marking Scheme:
Evaluating minimum value $= -1$: 1.0 Mark
Correct Answer: $-1$
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