Application of Integrals Question - CBSE

Question

Area bounded by the curve $y = x^3$, the $x$-axis and the ordinates $x = -2$ and $x = 1$ is:
(a) $\dfrac{17}{4}$ sq. units
(b) $\dfrac{15}{4}$ sq. units
(c) $\dfrac{9}{4}$ sq. units
(d) $\dfrac{13}{4}$ sq. units

Accepted Answer

$\int_{-2}^0 (-x^3) dx + \int_0^1 x^3 dx = 4 + 1/4 = 17/4$. [1.0 Mark]

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🎯 Official CBSE Marking Scheme:
Evaluating total area $= 17/4$ sq. units: 1.0 Mark

Question:

Step-by-Step Solution

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