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Three Dimensional Geometry
NCERT Exemplar Class 12
CBSE
Grade 12
Question:
The equation of line passing through $(1, 2, 3)$ and parallel to vector $3\hat{i} + 2\hat{j} - 2\hat{k}$ is: (a) $\dfrac{x-1}{3} = \dfrac{y-2}{2} = \dfrac{z-3}{-2}$ (b) $\dfrac{x-3}{1} = \dfrac{y-2}{2} = \dfrac{z+2}{3}$ (c) $\dfrac{x+1}{3} = \dfrac{y+2}{2} = \dfrac{z+3}{-2}$ (d) None of these
Step-by-Step Solution
Standard line equation (x-x0)/a = (y-y0)/b = (z-z0)/c. [1.0 Mark]
--- 🎯 Official CBSE Marking Scheme: Selecting $\dfrac{x-1}{3} = \dfrac{y-2}{2} = \dfrac{z-3}{-2}$: 1.0 Mark