Area Under the Curve
Area of $\min\{\sin x,\cos x\}$
nta_pyq_2024_apr
Grade 12
Question:
Let the area of the region enclosed by $y=\min\{\sin x,\cos x\}$ and the $x$-axis between $x=-\pi$ to $x=\pi$ be $A$. Then $A^2$ is equal to ___________.
Step-by-Step Solution
Key Concept: Piecewise integration over $[-\pi,\pi]$: $A=4$.
$A=4$. $A^2=16$.
Correct Answer: 16