Three Dimensional Geometry Question - CBSE

Question

Find the foot of perpendicular drawn from point $P(1, 6, 3)$ to the line $\dfrac{x}{1} = \dfrac{y-1}{2} = \dfrac{z-2}{3}$.

Accepted Answer

$\vec{PM} \cdot (1, 2, 3) = 14\lambda - 14 = 0 \Rightarrow \lambda = 1$. [1.5 Marks]
Foot of perpendicular $M = (1, 3, 5)$. [1.5 Marks]

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🎯 Official CBSE Marking Scheme:
Setting up perpendicular dot product equation: 1.5 Marks
Evaluating foot of perpendicular $M = (1, 3, 5)$: 1.5 Marks

Question:

Step-by-Step Solution

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