Definite Integration
Definite — Polynomial
Grade 12

Question:

<p>Find \(\displaystyle\int_0^1 x^n(1-x)^n\,dx\) [JEE Main 2021]</p>
(n!)^2/(2n+1)!
1/(n+1)
(n!)^2/(2n)!
1/(2n+1)

Step-by-Step Solution

Key Concept: Beta function: \int_0^1 xⁿ(1-x)ⁿ dx = B(n+1,n+1) = (n\!)^2/(2n+1)\!
<div class='solution'> <p>$\int_0^1 x^n(1-x)^n\,dx = B(n+1,n+1)=\frac{\Gamma(n+1)\Gamma(n+1)}{\Gamma(2n+2)}=\frac{(n\!)^2}{(2n+1)\!}$</p> </div>
Correct Answer: A

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