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Coordinate Geometry

Circles, Standard Equation

jee_main_2026_april_2_shift_1

Grade 12

Question:

The equation of the circle with center (1, -2) and radius 3 is:

A. (x-1)^2 + (y+2)^2 = 9

B. (x+1)^2 + (y-2)^2 = 9

C. (x-1)^2 + (y-2)^2 = 9

D. (x+1)^2 + (y+2)^2 = 9

Step-by-Step Solution

Key Concept: General equation of circle: (x-h)^2 + (y-k)^2 = r^2.

Step 1: Center (h, k) = (1, -2), radius r = 3. Step 2: (x-1)^2 + (y+2)^2 = 9.

Correct Answer: A

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