Limits
0/0 form; substitution
Grade Class 12

Question:

$\displaystyle\lim_{x\to\pi/3}\frac{\sin(\pi/3-x)}{2\cos x-1}$ is equal to
$\dfrac{2}{\sqrt3}$
$\dfrac{1}{\sqrt3}$
$\sqrt3$
$\dfrac{1}{2}$

Step-by-Step Solution

Key Concept: Let $t=x-\pi/3\to0$. Denominator: $2\cos(t+\pi/3)-1\approx-\sqrt3\,t$. Numerator: $\sin(-t)\approx-t$. Ratio $=1/\sqrt3$.
$\lim=\dfrac{-t}{-\sqrt3\,t}=\dfrac{1}{\sqrt3}$.
Correct Answer: 2

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