Integrals
NCERT Class 12
CBSE
Grade 12
Question:
The value of $\int_1^e \dfrac{1 + \log x}{x} dx$ is:
(a) $\dfrac{3}{2}$
(b) $\dfrac{1}{2}$
(c) $1$
(d) $2$
Step-by-Step Solution
$\left[ \dfrac{t^2}{2} \right]_1^2 = \dfrac{4-1}{2} = \dfrac{3}{2}$. [1.0 Mark]
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🎯 Official CBSE Marking Scheme:
Evaluating definite integral $= 3/2$: 1.0 Mark
Correct Answer: $\dfrac{3}{2}$
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