Application of Derivatives
NCERT Class 12
CBSE
Grade 12
Question:
The absolute minimum value of $f(x) = \sin x + \cos x$ in $[0, \pi]$ is:
(a) $-1$
(b) $\sqrt{2}$
(c) $1$
(d) $0$
Step-by-Step Solution
$f(0) = 1, f(\pi/4) = \sqrt{2}, f(\pi) = -1 \Rightarrow \text{Abs Min} = -1$. [1.0 Mark]
---
🎯 Official CBSE Marking Scheme:
Evaluating absolute minimum $= -1$: 1.0 Mark
Correct Answer: $-1$
Confused by the solution? Ask the AI to explain a specific step, tell you where you went wrong, or break down the key trap in this question.