Determinants
NCERT Class 12
CBSE
Grade 12
Question:
Find value of $k$ if area of triangle with vertices $(k, 0), (4, 0), (0, 2)$ is $4$ sq. units.
Step-by-Step Solution
$-2(k - 4) = \pm 8 \Rightarrow -2k + 8 = \pm 8$. [1.0 Mark]
$k = 0$ or $k = 8$. [1.0 Mark]
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🎯 Official CBSE Marking Scheme:
Setting up determinant equation: 1.0 Mark
Evaluating $k = 0, 8$: 1.0 Mark
Correct Answer:
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