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Triangles
RD Sharma
CBSE
Grade 10

Question:

In $\Delta ABC$, $DE \parallel BC$ intersecting $AB$ at $D$ and $AC$ at $E$. If $AD/DB = 3/4$ and $AC = 15\text{ cm}$, then $AE$ is:
(a) $6.43\text{ cm}$
(b) $6.0\text{ cm}$
(c) $9.0\text{ cm}$
(d) $4.5\text{ cm}$

Step-by-Step Solution

Key Concept: $\dfrac{AE}{AC} = \dfrac{AD}{AB} = \dfrac{3}{7} \Rightarrow AE = \dfrac{3}{7} \times 15 = \dfrac{45}{7} = 6.43\text{ cm}$.
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Correct Answer: $6.43\text{ cm}$
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