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Coordinate Geometry
CH07 Question Bank
CBSE_CH07_QUESTION_BANK
Grade 10

Question:

Find the value(s) of $k$ for which the distance between the points $(2,3)$ and $(10,k)$ is $10$ units.

Step-by-Step Solution

Key Concept: Set up the distance formula equation and solve for k.
$\sqrt{64+(k-3)^2}=10\Rightarrow(k-3)^2=36$. [1.0 Mark]

$k-3=\pm6\Rightarrow k=9$ or $k=-3$. [1.0 Mark]

Correct Answer:
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