Trigonometry & Inverse Trigonometry
Trigonometric Identities
Grade 11
Question:
<p>If <span>\(\tan B = \frac{\sin A \cos A}{1 - n\cos^2 A}\)</span>, then <span>\(\tan(A + B)\)</span> equals</p>
<p>(a) <span>\(\frac{\sin A}{(1-n)\cos A}\)</span></p>
<p>(b) <span>\(\frac{(n-1)\cos A}{\sin A}\)</span></p>
<p>(c) <span>\(\frac{\sin A}{(n-1)\cos A}\)</span></p>
<p>(d) <span>\(\frac{\sin A}{(n+1)\cos A}\)</span></p>
Step-by-Step Solution
Key Concept: Use the addition formula for tangent: <span>$\tan(A+B) = \frac{\tan A + \tan B}{1 - \tan A \tan B}$</span>
<p>Solution not provided in the text.</p>
Correct Answer: C