Coordinate Geometry
NCERT Exemplar
CBSE
Grade 10
Question:
The perimeter of a triangle with vertices $(0, 4), (0, 0)$ and $(3, 0)$ is:
(a) $5$
(b) $12$
(c) $11$
(d) $7 + \sqrt{5}$
Step-by-Step Solution
Key Concept: The vertices form a right triangle with legs of length 4 and 3.
Side 1 (along y-axis): length $4$. Side 2 (along x-axis): length $3$. [0.5 Mark]
Hypotenuse $= \sqrt{3^2 + 4^2} = \sqrt{25} = 5$. Perimeter $= 3 + 4 + 5 = 12$. [0.5 Mark]
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🎯 Official CBSE Marking Scheme:
Finding side lengths 3, 4, 5: 0.5 Mark
Calculating perimeter $= 12$: 0.5 Mark
Correct Answer: $12$
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