Step-by-Step Solution
Key Concept: Lines are coplanar when the scalar triple product of a connecting vector and both direction vectors equals zero.
Two lines are coplanar if the determinant condition is satisfied. Setting up the determinant with direction and position vectors of both lines, we solve $2(2-3)+3(3+3)+\lambda(-3-2) = 0$, yielding $\lambda = 4$. With $\lambda = 4$, we verify using $\sin^{-1}\sin 4 = \sin^{-1}\sin(\pi-4) = \pi - 4$.
Correct Answer: 4