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Application of Derivatives
NCERT Class 12
CBSE
Grade 12

Question:

The edge of a variable cube is increasing at the rate of $3\text{ cm/s}$. How fast is the volume of the cube increasing when the edge is $10\text{ cm}$ long?

Step-by-Step Solution

$\dfrac{dV}{dt} = 3x^2 \dfrac{dx}{dt}$. [1.0 Mark]
$= 3(100)(3) = 900\text{ cm}^3/\text{s}$. [1.0 Mark]

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🎯 Official CBSE Marking Scheme:
Differentiating volume formula: 1.0 Mark
Evaluating rate $= 900$ cm$^3$/s: 1.0 Mark

Correct Answer:
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